In an LCR series circuit at resonance: | vedclass

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(D) In an $LCR$ series circuit, the impedance $Z$ is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$.At resonance, the inductive reactance $X_L$ equals the

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the current and voltage are in phase.

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(D) In an $LCR$ series circuit, the impedance $Z$ is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$.At resonance, the inductive reactance $X_L$ equals the capacitive reactance $X_C$, i.e.,$X_L = X_C$.Therefore, the impedance $Z$ becomes $Z = \sqrt{R^2 + 0} = R$, which is the minimum possible value of impedance.Since $Z$ is minimum, the current $I = \frac{V}{Z}$ is maximum.Also, at resonance, the phase angle $\phi$ is given by $	an \phi = \frac{X_L - X_C}{R} = 0$, which implies $\phi = 0$.Since the phase angle is $0$, the current and voltage are in the same phase.

In an $LCR$ series circuit at resonance:

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