In an alpha-decay,the kinetic energy of the a | vedclass

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(B) The kinetic energy of an $\alpha$-particle in an $\alpha$-decay is given by the formula:$K_{\alpha} = \left( \frac{A-4}{A} \right) Q$where $A$ is

Vedclass · Accepted Answer

$100$

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(B) The kinetic energy of an $\alpha$-particle in an $\alpha$-decay is given by the formula:$K_{\alpha} = \left( \frac{A-4}{A} \right) Q$where $A$ is the mass number of the mother nucleus and $Q$ is the $Q$-value of the reaction.Given:$K_{\alpha} = 48 \, MeV$$Q = 50 \, MeV$Substituting these values into the formula:$48 = \left( \frac{A-4}{A} \right) 50$$48A = 50(A - 4)$$48A = 50A - 200$$2A = 200$$A = 100$Thus,the mass number of the mother nucleus is $100$.

In an $\alpha$-decay,the kinetic energy of the $\alpha$-particle is $48 \, MeV$ and the $Q$-value of the reaction is $50 \, MeV$. The mass number of the mother nucleus is:

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