The energy released by the fission of one ura | vedclass

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(B) The power $P$ produced is given by the product of the number of fissions per second $(n)$ and the energy released per fission $(E)$.$P = n 	imes

Vedclass · Accepted Answer

$2 	imes 10^{11}$

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(B) The power $P$ produced is given by the product of the number of fissions per second $(n)$ and the energy released per fission $(E)$.$P = n 	imes E$Given:$P = 6.4 	ext{ W} = 6.4 	ext{ J/s}$$E = 200 	ext{ MeV} = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$Rearranging for $n$:$n = \frac{P}{E}$$n = \frac{6.4}{3.2 	imes 10^{-11}}$$n = 2 	imes 10^{11} 	ext{ fissions/second}$Thus,the correct option is $B$.

The energy released by the fission of one uranium atom is $200 \text{ MeV}$. The number of fissions per second required to produce $6.4 \text{ W}$ power is $\qquad$ .

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