In an H_2 gas process, PV^2 = text{constant}. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a polytropic process $PV^x = 	ext{constant}$, the work done is given by $W = \frac{nR \Delta T}{1-x}$.Here, $x = 2$, so $W = \frac{nR \Delta

Vedclass · Accepted Answer

$-0.4$

Vedclass · Answer

(C) For a polytropic process $PV^x = 	ext{constant}$, the work done is given by $W = \frac{nR \Delta T}{1-x}$.Here, $x = 2$, so $W = \frac{nR \Delta T}{1-2} = -nR \Delta T$.For a diatomic gas like $H_2$, the change in internal energy is $\Delta U = n C_v \Delta T = n \left( \frac{5}{2}R ight) \Delta T = 2.5 nR \Delta T$.The ratio of work done to the change in internal energy is $\frac{W}{\Delta U} = \frac{-nR \Delta T}{2.5 nR \Delta T} = -\frac{1}{2.5} = -0.4$.

In an $H_2$ gas process, $PV^2 = \text{constant}$. The ratio of work done by the gas to the change in its internal energy is:

Similar Questions

An ideal gas expands in such a way that $PV^2 =$ constant throughout the process.

$1 \, \text{mole}$ of an ideal monoatomic gas at temperature $T_0$ expands slowly according to the law $P = KV$,where $K$ is a constant. If the final temperature of the gas is $2T_0$,find the heat supplied to the gas.

The variation of pressure $P$ with volume $V$ for an ideal diatomic gas is parabolic as shown in the figure. The molar specific heat of the gas during this process is

$A$ monatomic ideal gas undergoes a process in which the ratio of $P$ to $V$ at any instant is constant and equals to $1$. What is the molar heat capacity of the gas?

$A$ gas obeys the relation $P^2V = \text{constant}$. The initial temperature and volume are $T_0$ and $V_0$. If the gas expands to a volume $2V_0$, what will be its final temperature?

Vedclass Test Series

Exam Paper Generator

Online Exam Module