In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be

The $r.m.s.$ value of current for a variable current $i = i_1 \cos \omega t + i_2 \sin \omega t$ is:

An $AC$ current is given by the expression,$I(t) = 50 \sin(200 \pi t)$ in amperes. The frequency and $RMS$ value of the current respectively are

At time $t=0 \text{ s}$, the voltage of an $AC$ generator starts from $0 \text{ V}$ and becomes $2 \text{ V}$ at time $t=\frac{1}{100 \pi} \text{ s}$. The voltage increases up to $100 \text{ V}$, after which it starts to decrease. Find the frequency of the generator. (in $\text{ Hz}$)

$A$ periodic voltage $V$ varies with time $t$ as shown in the figure. $T$ is the time period. The $r.m.s.$ value of the voltage is:

The direct current which would give the same heating effect in an equal constant resistance as the current shown in the figure,i.e.,the $r.m.s.$ current,is.....$A$