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(C) The mirror formula is given by $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.For a concave mirror,using sign convention,$u$ and $v$ are negative. Let

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(C) The mirror formula is given by $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.For a concave mirror,using sign convention,$u$ and $v$ are negative. Let their magnitudes be $u$ and $v$. Then $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$,which can be written as $v = \frac{uf}{u-f}$.As $u 	o f$,$v 	o \infty$.As $u 	o \infty$,$v 	o f$.This represents a rectangular hyperbola where $v$ decreases as $u$ increases,which corresponds to the curve shown in graph $C$.

In an experiment to find the focal length of a concave mirror,a graph is drawn between the magnitudes of $u$ and $v$. The graph looks like:

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