The image formed by a concave mirror is

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(C) Using the mirror equation,$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Rearranging for image distance,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.For a

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certainly real if the object is virtual.

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(C) Using the mirror equation,$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$.Rearranging for image distance,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$.For a concave mirror,the focal length $f$ is negative $(f If the object is virtual,the object distance $u$ is positive $(u > 0)$. Substituting these into the equation,$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$ results in a negative value for $\frac{1}{v}$,meaning $v If the object is real,the object distance $u$ is negative $(u < 0)$. In this case,the image distance $v$ can be positive or negative depending on whether the object is placed between the pole and the focus or beyond the focus.

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