In an insulated parallel-plate capacitor of capacitance $C$,the four surfaces have charges $Q_1, Q_2, Q_3$ and $Q_4$ as shown. The potential difference between the plates is
- A$\frac{Q_2 - Q_3}{2C}$
- B$\frac{Q_2 + 2Q_3}{2C}$
- C$\frac{Q_1 + Q_4}{2C}$
- D$\frac{Q_1 + Q_2 + Q_3 + Q_4}{2C}$
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