In an isobaric process,the work done by a dia | vedclass

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(A) For an isobaric process,the work done $W$ and heat supplied $Q$ are given by:$W = n R \Delta T$$Q = n C_p \Delta T$Since $C_p = \frac{f}{2} R + R

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$35$

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(A) For an isobaric process,the work done $W$ and heat supplied $Q$ are given by:$W = n R \Delta T$$Q = n C_p \Delta T$Since $C_p = \frac{f}{2} R + R = (\frac{f}{2} + 1) R$,we have:$\frac{W}{Q} = \frac{n R \Delta T}{n (\frac{f}{2} + 1) R \Delta T} = \frac{1}{\frac{f}{2} + 1}$For a diatomic gas,the degrees of freedom $f = 5$.Substituting $f = 5$:$\frac{W}{Q} = \frac{1}{\frac{5}{2} + 1} = \frac{1}{\frac{7}{2}} = \frac{2}{7}$Therefore,$Q = \frac{7}{2} W$.Given $W = 10 \ J$,we get:$Q = \frac{7}{2} 	imes 10 = 35 \ J$.

Column-$I$	Column-$II$
$(a)$ Horizontal line parallel to $V$-axis	$(i)$ Adiabatic process
$(b)$ Vertical line parallel to $P$-axis	$(ii)$ Isobaric process
	$(iii)$ Isochoric process

In an isobaric process,the work done by a diatomic gas is $10 \ J$. The heat given to the gas will be (in $J$):

Similar Questions

Match the graphs in Column-$I$ with the processes in Column-$II$:
Column-$I$ Column-$II$
$(a)$ Horizontal line parallel to $V$-axis $(i)$ Adiabatic process
$(b)$ Vertical line parallel to $P$-axis $(ii)$ Isobaric process
$(iii)$ Isochoric process

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