In an optical instrument- microscope, the wavelengths of light used are $\lambda_1 = 6800 \text{ Å}$ and $\lambda_2 = 5100 \text{ Å}$. The ratio of the resolving power of the microscope corresponding to $\lambda_1$ to that for $\lambda_2$ is

  • A
    $9 : 16$
  • B
    $5 : 4$
  • C
    $4 : 3$
  • D
    $3 : 4$

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