In an aqueous solution containing AgCl_{(s)}, | vedclass

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Question

(A) For the dissolution of the salts in equilibrium with a common $[Ag^{+}]$ ion concentration:$K_{sp}(AgCl) = [Ag^{+}][Cl^{-}] = 10^{-10}$$K_{sp}(AgB

Vedclass · Accepted Answer

$10^6 : 10^3 : 1$

Vedclass · Answer

(A) For the dissolution of the salts in equilibrium with a common $[Ag^{+}]$ ion concentration:$K_{sp}(AgCl) = [Ag^{+}][Cl^{-}] = 10^{-10}$$K_{sp}(AgBr) = [Ag^{+}][Br^{-}] = 10^{-13}$$K_{sp}(AgI) = [Ag^{+}][I^{-}] = 10^{-16}$Dividing the expressions,we get:$\frac{[Cl^{-}]}{[Br^{-}]} = \frac{K_{sp}(AgCl)}{K_{sp}(AgBr)} = \frac{10^{-10}}{10^{-13}} = 10^3$$\frac{[Br^{-}]}{[I^{-}]} = \frac{K_{sp}(AgBr)}{K_{sp}(AgI)} = \frac{10^{-13}}{10^{-16}} = 10^3$Thus,$[Cl^{-}] = 10^3 [Br^{-}]$ and $[I^{-}] = 10^{-3} [Br^{-}]$.Substituting these into the ratio $[Cl^{-}] : [Br^{-}] : [I^{-}]$:$10^3 [Br^{-}] : [Br^{-}] : 10^{-3} [Br^{-}] = 10^3 : 1 : 10^{-3} = 10^6 : 10^3 : 1$.

In an aqueous solution containing $AgCl_{(s)}$,$AgBr_{(s)}$,and $AgI_{(s)}$,find the ratio $[Cl^{-}] : [Br^{-}] : [I^{-}]$ at equilibrium if $K_{sp}(AgCl) = 10^{-10}$,$K_{sp}(AgBr) = 10^{-13}$,and $K_{sp}(AgI) = 10^{-16}$.

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