In the case of an orbiting satellite,if the r | vedclass

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Question

(D) For a satellite of mass $m$ orbiting a planet of mass $M$ at a distance $r$:Kinetic Energy $(KE)$ = $\frac{GMm}{2r}$Potential Energy $(PE)$ = $-\f

Vedclass · Accepted Answer

Both $(A)$ and $(B)$ are wrong

Vedclass · Answer

(D) For a satellite of mass $m$ orbiting a planet of mass $M$ at a distance $r$:Kinetic Energy $(KE)$ = $\frac{GMm}{2r}$Potential Energy $(PE)$ = $-\frac{GMm}{r}$Total Energy $(E)$ = $-\frac{GMm}{2r}$If the radius $r$ is decreased:$1$. Since $KE = \frac{GMm}{2r}$,as $r$ decreases,$KE$ increases.$2$. Since $PE = -\frac{GMm}{r}$,as $r$ decreases,the magnitude $\frac{GMm}{r}$ increases,making the negative value more negative. Thus,$PE$ decreases.Therefore,both statements $(A)$ and $(B)$ are incorrect,making option $(D)$ the correct choice.

In the case of an orbiting satellite,if the radius of the orbit is decreased,then:

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