In the case of $NPN$ transistors,the collector current is always less than the emitter current because:
- ACollector side is reverse biased and emitter side is forward biased
- BAfter electrons are lost in the base,only the remaining ones reach the collector
- CCollector side is forward biased and emitter side is reverse biased
- DCollector being reverse biased attracts fewer electrons
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Similar Questions
In a common emitter transistor amplifier,the load resistance is $6.5 \text{ k}\Omega$ and the input resistance is $1.3 \text{ k}\Omega$. If the current gain is $78$,the voltage gain is:
Which of the following statements is true regarding transistor configurations?
Easy
View SolutionIn an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.
Difficult
View SolutionIn the following common emitter circuit, if $\beta=100$, $V_{CE}=7 \, V$, $V_{BE}$ is negligible, and $R_C=2 \, k\Omega$, then $I_B=$ (in $\, mA$)?
If an emitter current is changed by $4\, mA$,the collector current changes by $3.5\, mA$. The value of $\beta$ will be
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