In common emitter mode of a transistor, the d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: $\beta = 20$, $I_{E} = 7 \,mA$.We know that the current gain in common emitter mode is defined as $\beta = \frac{I_{C}}{I_{B}}$.Also, the r

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(D) Given: $\beta = 20$, $I_{E} = 7 \,mA$.We know that the current gain in common emitter mode is defined as $\beta = \frac{I_{C}}{I_{B}}$.Also, the relationship between emitter current, collector current, and base current is $I_{E} = I_{C} + I_{B}$, which implies $I_{B} = I_{E} - I_{C}$.Substituting $I_{B}$ in the gain formula: $\beta = \frac{I_{C}}{I_{E} - I_{C}}$.Rearranging the equation: $20 = \frac{I_{C}}{7 - I_{C}}$.$20(7 - I_{C}) = I_{C}$.$140 - 20I_{C} = I_{C}$.$140 = 21I_{C}$.$I_{C} = \frac{140}{21} = \frac{20}{3} \,mA$.

In common emitter mode of a transistor, the d.c. current gain is $20$, and the emitter current is $7 \,mA$. The collector current is (in $/ 3 \,mA$)

Similar Questions

The input voltage applied to a $CE$ amplifier is $v_i = 0.2 \sin(1000t) \text{ V}$. If the voltage gain of the amplifier is $10$,the equation for the output voltage is ....... $\text{V}$.

When the transistor is used as an amplifier,

In the symbol of a transistor,the arrow indicates the direction of:

In a junction transistor, the collector current changes by $6.8 \,mA$, if the emitter current is changed by $7 \,mA$. For such a transistor, the current amplification factor is

In the following transistor circuit,$R_i$ is the input resistance and $R_0$ is the output resistance. The approximate voltage gain for the circuit is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module