In a cyclic quadrilateral ABCD,if angle A = a | vedclass

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(D) In a cyclic quadrilateral,the sum of opposite angles is $180^{\circ}$.Given that $ABCD$ is a cyclic quadrilateral,therefore $\angle A + \angle C =

Vedclass · Accepted Answer

$90$

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(D) In a cyclic quadrilateral,the sum of opposite angles is $180^{\circ}$.Given that $ABCD$ is a cyclic quadrilateral,therefore $\angle A + \angle C = 180^{\circ}$.It is also given that $\angle A = \angle C$.Substituting $\angle A$ for $\angle C$ in the first equation,we get $\angle A + \angle A = 180^{\circ}$.$2\angle A = 180^{\circ}$.Therefore,$\angle A = 180^{\circ} / 2 = 90^{\circ}$.

In a cyclic quadrilateral $ABCD$,if $\angle A = \angle C$,then $\angle A = $ ........... (in $^{\circ}$)

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