In the figure,ABCD is a parallelogram,AE perp | vedclass

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(D) We are given that $ABCD$ is a parallelogram with $AE \perp DC$ and $CF \perp AD$.Given $AB = 16 \, cm, AE = 8 \, cm$ and $CF = 10 \, cm$.Since $AB

Vedclass · Accepted Answer

$12.8$

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(D) We are given that $ABCD$ is a parallelogram with $AE \perp DC$ and $CF \perp AD$.Given $AB = 16 \, cm, AE = 8 \, cm$ and $CF = 10 \, cm$.Since $ABCD$ is a parallelogram,opposite sides are equal,so $CD = AB = 16 \, cm$.The area of a parallelogram is given by the product of its base and the corresponding height.Area of parallelogram $ABCD = CD 	imes AE = 16 \, cm 	imes 8 \, cm = 128 \, cm^2$.Also,the area of the same parallelogram can be calculated using base $AD$ and height $CF$.Area of parallelogram $ABCD = AD 	imes CF$.Substituting the known values,we get $128 = AD 	imes 10$.Therefore,$AD = \frac{128}{10} = 12.8 \, cm$.

In the figure,$ABCD$ is a parallelogram,$AE \perp DC$ and $CF \perp AD$. If $AB = 16 \, cm, AE = 8 \, cm$ and $CF = 10 \, cm$,find $AD$. (in $, cm$)

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