In a first-order reaction,the concentration o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ Substituting the given va

Vedclass · Accepted Answer

$12.50$

Vedclass · Answer

(B) For a first-order reaction,the rate constant $k$ is given by the formula: $k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$ Substituting the given values: $k = \frac{2.303}{45 \, min} \log \frac{0.80}{0.06}$ $k = \frac{2.303}{45} \log(13.33) \approx \frac{2.303}{45} 	imes 1.1248 \approx 0.05756 \, min^{-1}$ The half-life $(t_{1/2})$ is calculated as: $t_{1/2} = \frac{0.693}{k}$ $t_{1/2} = \frac{0.693}{0.05756} \approx 12.04 \, min$. Note: Based on standard calculation,the closest option is $12.50 \, min$.

In a first-order reaction,the concentration of the reactant decreases from $0.80 \, mol \, L^{-1}$ to $0.06 \, mol \, L^{-1}$ in $45 \, min$. Calculate the half-life $(t_{1/2})$. (in $, min$)

Similar Questions

$A$ reaction which is of first order with respect to reactant $A$,has a rate constant $6 \, min^{-1}$. If we start with $[A] = 0.5 \, mol \, L^{-1}$,when would $[A]$ reach the value of $0.05 \, mol \, L^{-1}$?

Which of the following is an example of a first-order reaction?

What is the rate constant of a first-order reaction if $0.08 \ mol$ of reactant reduces to $0.02 \ mol$ in $23.03 \ min$ (in $min^{-1}$)?

Consider the first order reaction $R \to P$. The fraction of molecules decomposed in the given first order reaction can be expressed as:

Give examples of first-order reactions.

Vedclass Test Series

Exam Paper Generator

Online Exam Module