In the following reaction: $CH_3COOH + PCl_5$ $\rightarrow (A)$ $\xrightarrow[(2) H_2O]{(1) CH_3MgBr} (B)$,product $(B)$ would be:

  • A
    $CH_3-CH_2-CH(OH)-CH_3$
  • B
    $CH_3-CO-C_6H_5$
  • C
    $CH_3-CH(OH)-CH_3$
  • D
    $CH_3-C(OH)(CH_3)_2$

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