In the following reaction yMnO_4^- + xH^{+} + | vedclass

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(B) The balanced redox reaction is: $2MnO_4^- + 16H^{+} + 5C_2O_4^{2-} 	o 2Mn^{2+} + 10CO_2 + 8H_2O$ Comparing this with the given equation $yMnO_4^-

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$16$ and $2$

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(B) The balanced redox reaction is: $2MnO_4^- + 16H^{+} + 5C_2O_4^{2-} 	o 2Mn^{2+} + 10CO_2 + 8H_2O$ Comparing this with the given equation $yMnO_4^- + xH^{+} + C_2O_4^{2-} 	o yMn^{2+} + 2CO_2 + \frac{x}{2}H_2O$,we divide the balanced equation by $5$ to match the coefficient of $C_2O_4^{2-}$ as $1$: $\frac{2}{5}MnO_4^- + \frac{16}{5}H^{+} + C_2O_4^{2-} 	o \frac{2}{5}Mn^{2+} + 2CO_2 + \frac{8}{5}H_2O$ However,the question implies integer coefficients for the balanced equation. For $2MnO_4^- + 16H^{+} + 5C_2O_4^{2-} 	o 2Mn^{2+} + 10CO_2 + 8H_2O$,we have $y = 2$ and $x = 16$.

In the following reaction $yMnO_4^- + xH^{+} + C_2O_4^{2-} \to yMn^{2+} + 2CO_2 + \frac{x}{2}H_2O$,the values of $x$ and $y$ are:

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