(C) The genotype of the heterozygous parent is $Rr$.When this plant is selfed $(Rr \times Rr)$,the resulting progeny genotypes are $RR, Rr, Rr, rr$.Th

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(C) The genotype of the heterozygous parent is $Rr$.When this plant is selfed $(Rr \times Rr)$,the resulting progeny genotypes are $RR, Rr, Rr, rr$.The phenotypic ratio is $3$ round : $1$ wrinkled.The parental phenotype is 'round' (since the parent is heterozygous for round seeds).Out of the total $1600$ seeds,the number of round-seeded plants is $\frac{3}{4} \times 1600 = 1200$.Therefore,$1200$ seedlings will exhibit the parental phenotype.

Class 12 Biology Principles of Inheritance and Variation Inheritance of one gene

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In garden pea,round shape of seeds is dominant over wrinkled shape. $A$ pea plant heterozygous for round shape of seed is selfed and $1600$ seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?

KCET 2014 All KCET

A
$400$
B
$1600$
C
$1200$
D
$800$

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Principles of Inheritance and Variation

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Inheritance of one gene

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In garden pea,round shape of seeds is dominant over wrinkled shape. $A$ pea plant heterozygous for round shape of seed is selfed and $1600$ seeds produced during the cross are subsequently germinated. How many seedlings would have the parental phenotype?

Similar Questions

When different alleles of the same gene are present in an individual,the individual is a

The proportion of plants that were dwarf and tall,respectively,in the $F_2$-generation of Mendel's experiment was?

When Mendel crossed a true-breeding white-flowered strain of peas with a true-breeding red-flowered strain,the individuals in the $F_2$ generation represented:

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