In half wave rectification,if the input frequency is $60\,Hz$,then the output frequency would be $\dots\dots\dots\,Hz$.

If an alternating voltage is applied across a $p-n$ junction diode in series with a load,then:

If a centre-tap transformer is used with two $p-n$ junction diodes for full-wave rectification,then the output voltage of the rectifier with respect to each diode is (secondary voltage of transformer $= V_s$)

The frequency of a given $AC$ signal is $N \ Hz$. When it is connected to a half-wave rectifier,the number of output pulses given by the rectifier in $1 \ s$ is:

The output current versus time curve of a rectifier is shown in the figure. The average value of the output current in this case is

An alternating voltage of $141.4\,V$ (rms) is applied to a vacuum diode as shown in the figure. The maximum potential difference across the condenser will be......$V$