In how many ways can a team of 11 players be | vedclass

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(B) Total players = $25$. Team size required = $11$. Number of players always to be included = $6$. Number of players always to be excluded = $5$. Rem

Vedclass · Accepted Answer

$2002$

Vedclass · Answer

(B) Total players = $25$. Team size required = $11$. Number of players always to be included = $6$. Number of players always to be excluded = $5$. Remaining players to be selected = $11 - 6 = 5$. Remaining pool of players to choose from = $25 - 6 - 5 = 14$. Therefore,the number of ways to form the team is $^{14}C_5$. $^{14}C_5 = \frac{14 	imes 13 	imes 12 	imes 11 	imes 10}{5 	imes 4 	imes 3 	imes 2 	imes 1} = 2002$.

In how many ways can a team of $11$ players be formed out of $25$ players,if $6$ out of them are always to be included and $5$ are always to be excluded?

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