In a hydrogenation reaction at $27\,^oC$,it is observed that the hydrogen gas pressure falls from $2\,atm$ to $1.2\,atm$ in $50\,min$. Calculate the rate of disappearance of hydrogen.

For the reaction,$5Br^-{_{\text{(aq)}}} + BrO_3^-{_{\text{(aq)}}} + 6H^+{_{\text{(aq)}}} \rightarrow 3Br_{2\text{(aq)}} + 3H_2O_{\text{(l)}}$,if $-\frac{\Delta[Br^{-}]}{\Delta t} = 0.05 \ mol \ L^{-1} \ min^{-1}$,then the value of $-\frac{\Delta[BrO_3^{-}]}{\Delta t}$ in $mol \ L^{-1} \ min^{-1}$ is:

$NO_2$ required for a reaction is produced by decomposition of $N_2 O_5$ in $CCl_4$ as per the equation $2 \, N_2 O_{5(g)} \rightarrow 4 NO_{2(g)} + O_{2(g)}$. The initial concentration of $N_2 O_5$ is $3 \, mol \, L^{-1}$ and it is $2.75 \, mol \, L^{-1}$ after $30 \, minutes$. The rate of formation of $NO_2$ is $x \times 10^{-3} \, mol \, L^{-1} \, min^{-1}$. The value of $x$ is . . . . . . .

For the reaction $H_2 + I_2 \rightarrow 2HI$,state the correct differential rate law.

For the chemical reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$,the rate of reaction can be expressed in terms of the concentration of $N_{2(g)}$,$H_{2(g)}$,or $NH_{3(g)}$ with respect to time. Identify the correct relationship between these rates.

In the reaction $2N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g)$, $N_2O_5$ disappears at a rate of $0.06 \text{ mol dm}^{-3} \text{s}^{-1}$. Calculate the rate of formation of $O_2(g)$.