In methyl alcohol solution,bromine reacts wit | vedclass

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(A) The reaction of ethylene with bromine in the presence of a nucleophilic solvent like methanol $(CH_3OH)$ proceeds through the formation of a cycli

Vedclass · Accepted Answer

The ion formed initially may react with $Br^{-}$ or $CH_3OH$

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(A) The reaction of ethylene with bromine in the presence of a nucleophilic solvent like methanol $(CH_3OH)$ proceeds through the formation of a cyclic bromonium ion intermediate. This cyclic bromonium ion is electrophilic in nature. It can be attacked by the bromide ion $(Br^-)$ to form $1, 2-dibromoethane$ or by the solvent molecule $(CH_3OH)$ to form $BrCH_2CH_2OCH_3$ after the loss of a proton. Thus,the product depends on which nucleophile attacks the intermediate.

In methyl alcohol solution,bromine reacts with ethylene to yield $BrCH_2CH_2OCH_3$ in addition to $1, 2-dibromoethane$ because:

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