In order to prepare 1-chloropropane,which of | vedclass

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(C) The reaction of $propan-1-ol$ with $SOCl_2$ in the presence of pyridine is a standard method for the preparation of chloroalkanes from alcohols. T

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propan$-1$-ol and $SOCl_2$ / pyridine

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(C) The reaction of $propan-1-ol$ with $SOCl_2$ in the presence of pyridine is a standard method for the preparation of chloroalkanes from alcohols. This reaction proceeds via an $S_N2$ mechanism,which ensures the formation of $1$-chloropropane without rearrangement. The reaction is: $CH_3CH_2CH_2OH + SOCl_2 \xrightarrow{	ext{pyridine}} CH_3CH_2CH_2Cl + SO_2 + HCl$. Option $A$ is incorrect because the addition of $HCl$ to propene follows Markovnikov's rule,yielding $2$-chloropropane. Option $B$ is incorrect because treatment of propene with $Cl_2$ leads to addition across the double bond,and subsequent treatment with $aq. KOH$ would likely result in substitution or elimination,not specifically $1$-chloropropane.

In order to prepare $1$-chloropropane,which of the following reactants can be employed?

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