In parallelogram ABCD,DM is an altitude corre | vedclass

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(B) The area of a parallelogram is given by the formula: $	ext{Area} = 	ext{base} 	imes 	ext{height}$.Here,the base is $AB = 15 	ext{ cm}$ and th

Vedclass · Accepted Answer

$24$

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(B) The area of a parallelogram is given by the formula: $	ext{Area} = 	ext{base} 	imes 	ext{height}$.Here,the base is $AB = 15 	ext{ cm}$ and the corresponding altitude is $DM$.Given,$	ext{ar}(ABCD) = 360 	ext{ cm}^2$.Substituting the values into the formula: $360 = 15 	imes DM$.To find $DM$,divide $360$ by $15$: $DM = \frac{360}{15} = 24 	ext{ cm}$.Therefore,the length of the altitude $DM$ is $24 	ext{ cm}$.

In parallelogram $ABCD$,$DM$ is an altitude corresponding to base $AB$. If $AB = 15 \text{ cm}$ and $\text{ar}(ABCD) = 360 \text{ cm}^2$,then $DM = \ldots \text{ cm}$.

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