In projectile motion,the modulus of the rate | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In projectile motion,the only force acting on the projectile is gravity,which acts vertically downwards.According to Newton's second law,the accel

Vedclass · Accepted Answer

is constant

Vedclass · Answer

(A) In projectile motion,the only force acting on the projectile is gravity,which acts vertically downwards.According to Newton's second law,the acceleration of the projectile is $\vec{a} = \vec{g}$,where $\vec{g}$ is the acceleration due to gravity.The rate of change of velocity is defined as the acceleration,i.e.,$\frac{d\vec{v}}{dt} = \vec{a}$.Therefore,the rate of change of velocity is $\vec{g}$.The modulus (magnitude) of the rate of change of velocity is $|\frac{d\vec{v}}{dt}| = |\vec{g}| = g$.Since $g$ is the acceleration due to gravity,which is constant throughout the motion,the modulus of the rate of change of velocity is constant.

In projectile motion,the modulus of the rate of change of velocity is:

Similar Questions

$A$ projectile crosses two walls of equal height $H$ symmetrically as shown. If the horizontal distance between the two walls is $d = 120\, m$ and the times at which the projectile crosses the walls are $t_1 = 2\, s$ and $t_2 = 6\, s$,then the range of the projectile is ........ $m$.

An aircraft executes a horizontal loop of radius $1.00 \; km$ with a steady speed of $900 \; km/h$. Compare its centripetal acceleration with the acceleration due to gravity.

Two bodies were thrown simultaneously from the origin: one straight up and the other at an angle of $60^{\circ}$ to the vertical. The initial velocity of each body is $10 \ m \ s^{-1}$. Neglecting air resistance, the distance between the two bodies after $t=2 \ s$ is (Use $g=10 \ m \ s^{-2}$):

$A$ body of mass $m$ is performing a $UCM$ in a circle of radius $r$ with speed $v$. The work done by the centripetal force in moving it through $\left(\frac{2}{3}\right)$ rd of the circular path is

$A$ particle moves along a circle with a constant angular speed $\omega$. Its displacement,with respect to the initial position of the particle at time $t = 0$,is plotted against time. The graph would look like:

Vedclass Test Series

Exam Paper Generator

Online Exam Module