In reaction $(1)$, $XeF_6$ undergoes complete hydrolysis to form $HF$ and $X$. In reaction $(2)$, $XeF_6$ undergoes partial hydrolysis to form $HF$, $Y$, and $Z$. The products $X, Y, Z$ respectively, are

• A
  $XeO_3, XeOF_4, XeO_2 F_2$
• B
  $XeO_3, XeO_2 F_2, XeOF_4$
• C
  $Xe, XeOF_4, XeO_2 F_2$
• D
  $XeO_3, O_2, XeO_2 F_2$