In sweet peas,genes C and P are necessary for | vedclass

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(C) For flowers to be coloured,both dominant genes $C$ and $P$ must be present (genotype $C-P-$).Given cross: $Cc\ pp 	imes cc\ Pp$.Gametes produced

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(C) For flowers to be coloured,both dominant genes $C$ and $P$ must be present (genotype $C-P-$).Given cross: $Cc\ pp 	imes cc\ Pp$.Gametes produced by $Cc\ pp$: $Cp$ and $cp$.Gametes produced by $cc\ Pp$: $cP$ and $cp$.Punnett square analysis:| | $Cp$ | $cp$ ||---|---|---|| $cP$ | $CcPp$ | $ccPp$ || $cp$ | $Ccpp$ | $ccpp$ |Out of the $4$ offspring,only $CcPp$ has both dominant genes $C$ and $P$,resulting in a coloured flower.The other three genotypes ($ccPp$,$Ccpp$,$ccpp$) lack at least one dominant gene,resulting in white flowers.Therefore,the percentage of coloured flowers is $(1/4) 	imes 100 = 25\%$.

In sweet peas,genes $C$ and $P$ are necessary for colour in flowers. The flowers are white in the absence of either or both the genes. What will be the percentage of coloured flowers in the offspring of the cross $Cc\ pp \times cc\ Pp$ (in $\%$)?

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