In terms of resistance R and time T,the dimen | vedclass

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(C) The dimensions of permeability $\mu$ are $[M L T^{-2} A^{-2}]$.The dimensions of permittivity $\varepsilon$ are $[M^{-1} L^{-3} T^4 A^2]$.The dime

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$[R^2]$

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(C) The dimensions of permeability $\mu$ are $[M L T^{-2} A^{-2}]$.The dimensions of permittivity $\varepsilon$ are $[M^{-1} L^{-3} T^4 A^2]$.The dimensions of resistance $R$ are $[M L^2 T^{-3} A^{-2}]$.Now,consider the ratio $\frac{\mu}{\varepsilon}$:$\frac{\mu}{\varepsilon} = \frac{[M L T^{-2} A^{-2}]}{[M^{-1} L^{-3} T^4 A^2]} = [M^2 L^4 T^{-6} A^{-4}]$.Now,compare this with the dimensions of $R^2$:$R^2 = ([M L^2 T^{-3} A^{-2}])^2 = [M^2 L^4 T^{-6} A^{-4}]$.Thus,the dimensions of $\frac{\mu}{\varepsilon}$ are equal to $[R^2]$.

In terms of resistance $R$ and time $T$,the dimensions of the ratio $\frac{\mu}{\varepsilon}$ of the permeability $\mu$ and permittivity $\varepsilon$ is:

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