In the adjoining figure,the tension in the string connecting blocks $A$ and $B$ is:

$A$ lift is tied with thick iron ropes having mass $M$. The maximum acceleration of the lift is $a \ m/s^2$ and the maximum safe stress is $S \ N/m^2$. The minimum diameter of the rope is

$A$ hanging mass $M$ is connected to a four times larger mass $(4M)$ by using a string-pulley arrangement as shown in the figure. The larger mass is placed on a horizontal ice slab and is being pulled by a $2Mg$ force. In this situation,the tension in the string is $\frac{x}{5}Mg$. Find the value of $x$. Neglect the mass of the string and the friction between the block (larger mass) and the ice slab. (Given $g$ = acceleration due to gravity)

$A$ block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $M/2$. If a force $2Mg$ is applied at one end of the rope,the force which the rope exerts on the block is -

As shown in the figure,two equal masses each of $2\, kg$ are suspended from a spring balance. The reading of the spring balance will be ......... $kg$.

In the system shown in the figure,there is no friction anywhere. The block $C$ $(2 \, kg)$ moves down by a distance $x_0 = 10 \, cm$ with respect to the wedge $D$ $(4 \, kg)$ when the system is released from rest. The velocity of $A$ $(1 \, kg)$ with respect to $B$ $(1 \, kg)$ will be $(g = 10 \, m/s^2)$ ......... $m/s$.