In the binomial expansion of $(a - b)^n, n \ge 5,$ the sum of the $5^{th}$ and $6^{th}$ terms is zero. Then $\frac{a}{b}$ is equal to

  • A
    $\frac{1}{6}(n - 5)$
  • B
    $\frac{1}{5}(n - 4)$
  • C
    $\frac{5}{n - 4}$
  • D
    $\frac{6}{n - 5}$

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