In the Boolean algebra,$(\overline {\bar A \cdot \bar B} ) \cdot A$ is equal to:
- A$\overline {A + B} $
- B$A$
- C$\overline {A \cdot B} $
- D$A + B$
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Similar Questions
Which of the following circuits correctly represents the following truth table?
$A$ $B$ $C$ $0$ $0$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $1$ $1$ $0$
| $A$ | $B$ | $C$ |
| $0$ | $0$ | $0$ |
| $0$ | $1$ | $0$ |
| $1$ | $0$ | $1$ |
| $1$ | $1$ | $0$ |
Justify the output waveform $(Y)$ of the $OR$ gate for the following inputs $A$ and $B$ given in the figure.
Medium
View SolutionFor a two-input $AND$ gate,the four entries are shown in the truth table. Identify the correct ones out of these ($A, B =$ input,$Y =$ output).
Entry $A$ $B$ $Y$ $1$ $0$ $1$ $0$ $2$ $1$ $0$ $0$ $3$ $1$ $1$ $1$ $4$ $0$ $0$ $1$
| Entry | $A$ | $B$ | $Y$ |
|---|---|---|---|
| $1$ | $0$ | $1$ | $0$ |
| $2$ | $1$ | $0$ | $0$ |
| $3$ | $1$ | $1$ | $1$ |
| $4$ | $0$ | $0$ | $1$ |
To get an output $Y = 1$ in the given circuit,which of the following inputs will be correct?
MediumNEET 2016
View SolutionIdentify the logic operation performed by the given circuit.
DifficultTS EAMCET 2022
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