In the case of rotational dynamics,which one of the following statements is correct?
$[\vec{\omega} = \text{angular velocity}, \vec{v} = \text{linear velocity}, \vec{r} = \text{radius vector}, \vec{\alpha} = \text{angular acceleration}, \vec{a} = \text{linear acceleration}, \vec{L} = \text{angular momentum}, \vec{p} = \text{linear momentum}, \vec{\tau} = \text{torque}, \vec{f} = \text{force}]$

  • A
    $\vec{v} = \vec{r} \times \vec{\omega}, \vec{\alpha} = \vec{r} \times \vec{a}, \vec{L} = \vec{r} \times \vec{p}, \vec{\tau} = \vec{f} \times \vec{r}$
  • B
    $\vec{v} = \vec{\omega} \times \vec{r}, \vec{\alpha} = \vec{a} \times \vec{r}, \vec{L} = \vec{p} \times \vec{r}, \vec{\tau} = \vec{r} \times \vec{f}$
  • C
    $\vec{v} = \vec{\omega} \times \vec{r}, \vec{\alpha} = \vec{a} \times \vec{r}, \vec{L} = \vec{r} \times \vec{p}, \vec{\tau} = \vec{r} \times \vec{f}$
  • D
    $\vec{v} = \vec{\omega} \times \vec{r}, \vec{\alpha} = \vec{a} \times \vec{r}, \vec{L} = \vec{p} \cdot \vec{r}, \vec{\tau} = \vec{r} \times \vec{f}$

Explore More

Similar Questions

$A$ particle falls freely near the surface of the earth. Consider a fixed point $O$ (not vertically below the particle) on the ground.

Difficult
View Solution

$A$ uniform metallic rod rotates about its perpendicular bisector with constant angular speed. If it is heated uniformly to raise its temperature slightly,what happens to its speed of rotation?

Fill in the blanks:
$(1)$ If the velocity of the center of mass of a body is $v_{cm} = 0$ and the angular velocity is $\omega = 0$,the body is said to be in ............. equilibrium.
$(2)$ Angular momentum is generated in a body when a ............. acts on it.
$(3)$ If a barrel is filled half with water,its center of gravity will move ............. .
$(4)$ The point at which the entire mass of a body is assumed to be concentrated is called the ............. .

For the pivoted slender rod of length $l$ as shown in the figure,the angular velocity as the bar reaches the vertical position after being released from the horizontal position is:

Difficult
View Solution

$A$ mass $M = 40 \ kg$ is fixed at the very edge of a long plank of mass $80 \ kg$ and length $1 \ m$ which is pivoted such that it is in equilibrium. How far (approx.) from the pivot should a mass of $100 \ kg$ be attached so that the plank starts rotating with an angular acceleration of $1 \ rad/s^2$?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo