In the circuit below,$A$ and $B$ represent two inputs and $C$ represents the output. The circuit represents:

  • A
    $AND$ gate
  • B
    $NOR$ gate
  • C
    $OR$ gate
  • D
    $NAND$ gate

Explore More

Similar Questions

In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?

In the Boolean algebra,$(\overline {\bar A \cdot \bar B} ) \cdot A$ is equal to:

The truth table for the given circuit of four $NAND$ gates is:

In Boolean algebra,$Y = A + B$ represents . . . . . .

The logic relation is given by $Y = \bar{A} \cdot B + A \cdot \bar{B}$. Construct this gate using $AND$,$OR$,and $NOT$ gates.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo