In the circuit shown,the transistor used has a current gain $\beta = 100$. What should be the base resistor $R_B$ so that $V_{CE} = 5\,V$ and $V_{BE} = 0\,V$?

In a common base amplifier,the phase difference between the input signal voltage and the output voltage is

The correct relationship between $\alpha$ and $\beta$ for a transistor is ........

The value of $I_c$ for the configuration shown is in $mA$.

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.