In the compound given below,the correct order | vedclass

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(B) The acidity of a proton depends on the stability of its conjugate base. $1$. Position $(X)$ is the carboxylic acid group $(-COOH)$,which is inhere

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$(X) > (Y) > (Z)$

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(B) The acidity of a proton depends on the stability of its conjugate base. $1$. Position $(X)$ is the carboxylic acid group $(-COOH)$,which is inherently more acidic than the ammonium groups $(-NH_3^+)$. $2$. Between the two ammonium groups $(Y)$ and $(Z)$,the position $(Y)$ is closer to the electron-withdrawing $-COOH$ group. The inductive effect ($-I$ effect) of the $-COOH$ group destabilizes the positive charge on the adjacent $-NH_3^+$ group at $(Y)$ more than at $(Z)$,making the proton at $(Y)$ more acidic than the one at $(Z)$. $3$. Therefore,the order of acidity is $(X) > (Y) > (Z)$.

In the compound given below,the correct order of the acidity of the positions $(X)$,$(Y)$ and $(Z)$ is:

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