In the electronic structure of acetic acid (C | vedclass

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(A) The chemical formula of acetic acid is $CH_3COOH$.Total valence electrons in $CH_3COOH$ are: $4(C) + 3(H) + 6(O) + 6(O) + 1(H) = 24$ electrons.In

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$16$ shared and $8$ unshared electrons

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(A) The chemical formula of acetic acid is $CH_3COOH$.Total valence electrons in $CH_3COOH$ are: $4(C) + 3(H) + 6(O) + 6(O) + 1(H) = 24$ electrons.In the Lewis structure of $CH_3COOH$:- There are $8$ single bonds ($C-H$ $	imes$ $3$,$C-C$ $	imes$ $1$,$C-O$ $	imes$ $1$,$O-H$ $	imes$ $1$,$C=O$ $	imes$ $1$ double bond).- Total shared electrons = $8 	ext{ bonds} 	imes 2 = 16$ shared electrons.- Unshared electrons (lone pairs) are on oxygen atoms: The carbonyl oxygen has $2$ lone pairs ($4$ electrons) and the hydroxyl oxygen has $2$ lone pairs ($4$ electrons).- Total unshared electrons = $4 + 4 = 8$ electrons.Therefore,there are $16$ shared and $8$ unshared electrons.

Column-$I$	Column-$II$
$(P)$ $\underline PCl_5 \to PCl_3 + Cl_2$	$(i)$ Change in hybridisation
$(Q)$ $\underline SO_3 \to \underline SO_2 + \frac{1}{2}O_2$	$(ii)$ Change in bond angle
$(R)$ $\underline NH_3 + H^{+} \to \underline NH_4^+$	$(iii)$ Change in shape
$(S)$ $H_2\underline O + H^{+} \to H_3\underline O^{+}$	$(iv)$ Change in oxidation state

In the electronic structure of acetic acid $(CH_3COOH)$,there are:

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