In the figure shown,a block of weight 10 , N | vedclass

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(C) The limiting friction force ${F_l}$ required to start the motion of the block is given by ${F_l} = {\mu _s}R$,where $R$ is the normal reaction for

Vedclass · Accepted Answer

Not move

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(C) The limiting friction force ${F_l}$ required to start the motion of the block is given by ${F_l} = {\mu _s}R$,where $R$ is the normal reaction force.Since the block is on a horizontal surface,$R = mg = 10 \, N$.Therefore,${F_l} = 0.4 	imes 10 \, N = 4 \, N$.This means a minimum force of $4 \, N$ is required to overcome static friction and initiate motion.The applied horizontal force is $3 \, N$.Since the applied force $(3 \, N)$ is less than the limiting friction $(4 \, N)$,the block will not move.Thus,the correct option is $(C)$.

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