In the following electrical circuit, the read | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given circuit consists of a $5 	ext{ V}$ $DC$ source, a silicon diode, and a resistor of $200 	ext{ } \Omega$ connected in series.Since the

Vedclass · Accepted Answer

$21.5$

Vedclass · Answer

(B) The given circuit consists of a $5 	ext{ V}$ $DC$ source, a silicon diode, and a resistor of $200 	ext{ } \Omega$ connected in series.Since the diode is forward-biased, it will conduct current when the applied voltage exceeds its knee voltage.The effective voltage across the resistor $(V_R)$ is given by:$V_R = V_{	ext{source}} - V_{	ext{knee}}$$V_R = 5 	ext{ V} - 0.7 	ext{ V} = 4.3 	ext{ V}$Using Ohm's law, the current $(I)$ flowing through the circuit is:$I = \frac{V_R}{R}$$I = \frac{4.3 	ext{ V}}{200 	ext{ } \Omega} = 0.0215 	ext{ A}$To convert the current into milliamperes (mA):$I = 0.0215 	imes 1000 	ext{ mA} = 21.5 	ext{ mA}$Therefore, the reading in the milliammeter is $21.5 	ext{ mA}$.

In the following electrical circuit, the reading in the milliammeter is (Take knee voltage of silicon diode $= 0.7 \text{ V}$) (in $\text{ mA}$)

Similar Questions

What is a depletion barrier?

The $I-V$ characteristics of a semiconductor diode are shown in the figure. The resistance of the diode at $V = -8 \text{ V}$ and $I_{d} = 10 \text{ mA}$ are respectively:

Assuming that the junction diode is ideal, find the current in the arrangement shown in the figure. (in $\text{mA}$)

The reverse breakdown voltage for a silicon diode is $6 \ V$ for a particular doping concentration and the forward bias voltage drop is $0.3 \ V$. Find the approximate current through the battery in the given circuit in $Amp$.

In a $p-n$ junction diode,the direction of diffusion current is from

Vedclass Test Series

Exam Paper Generator

Online Exam Module