Class 12Chemistry2 Aldehydes, Ketones and Carboxylic Acids: Carboxylic Acids and their DerivativesMix Examples-Carboxylic acids and Their derivative
MediumIn the following reactions,$P$,$Q$,$R$,and $S$ are the major products.
The correct statement$(s)$ about $P$,$Q$,$R$,and $S$ is (are)
$(A)$ $P$ and $Q$ are monomers of polymers dacron and glyptal,respectively.
$(B)$ $P$,$Q$,and $R$ are dicarboxylic acids.
$(C)$ Compounds $Q$ and $R$ are the same.
$(D)$ $R$ does not undergo aldol condensation and $S$ does not undergo Cannizzaro reaction.
The correct statement$(s)$ about $P$,$Q$,$R$,and $S$ is (are)
$(A)$ $P$ and $Q$ are monomers of polymers dacron and glyptal,respectively.
$(B)$ $P$,$Q$,and $R$ are dicarboxylic acids.
$(C)$ Compounds $Q$ and $R$ are the same.
$(D)$ $R$ does not undergo aldol condensation and $S$ does not undergo Cannizzaro reaction.
- A$C, D$
- B$C, A$
- C$C, B$
- D$C, D, A$
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Similar Questions
Product $(A)$ of the reaction is:
Match List-$I$ and List-$II$.
List-$I$ List-$II$ $(a)$ $R-COCl \to R-CHO$ $(i)$ $Br_2 / NaOH$ $(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$ $(ii)$ $H_2 / Pd-BaSO_4$ $(c)$ $R-CONH_2 \to R-NH_2$ $(iii)$ $Zn(Hg) / \text{Conc. } HCl$ $(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$ $(iv)$ $Cl_2 / \text{Red } P, H_2O$
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| $(a)$ $R-COCl \to R-CHO$ | $(i)$ $Br_2 / NaOH$ |
| $(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$ | $(ii)$ $H_2 / Pd-BaSO_4$ |
| $(c)$ $R-CONH_2 \to R-NH_2$ | $(iii)$ $Zn(Hg) / \text{Conc. } HCl$ |
| $(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$ | $(iv)$ $Cl_2 / \text{Red } P, H_2O$ |
Choose the correct answer from the options given below:
Match List-$I$ with List-$II$ :
List-$I$ (Chemical Reaction) List-$II$ (Reagent used) $(a)$ $CH_{3}COOCH_{2}CH_{3} \rightarrow CH_{3}CH_{2}OH$ $(i)$ $CH_{3}MgBr / H_{3}O^{+}$ ($1$ equivalent) $(b)$ $CH_{3}COOCH_{3} \rightarrow CH_{3}CHO$ $(ii)$ $H_{2}SO_{4} / H_{2}O$ $(c)$ $CH_{3}C \equiv N \rightarrow CH_{3}CHO$ $(iii)$ $DIBAL-H / H_{2}O$ $(d)$ $CH_{3}C \equiv N \rightarrow CH_{3}COCH_{3}$ $(iv)$ $SnCl_{2}, HCl / H_{2}O$
Choose the most appropriate match :
| List-$I$ (Chemical Reaction) | List-$II$ (Reagent used) |
|---|---|
| $(a)$ $CH_{3}COOCH_{2}CH_{3} \rightarrow CH_{3}CH_{2}OH$ | $(i)$ $CH_{3}MgBr / H_{3}O^{+}$ ($1$ equivalent) |
| $(b)$ $CH_{3}COOCH_{3} \rightarrow CH_{3}CHO$ | $(ii)$ $H_{2}SO_{4} / H_{2}O$ |
| $(c)$ $CH_{3}C \equiv N \rightarrow CH_{3}CHO$ | $(iii)$ $DIBAL-H / H_{2}O$ |
| $(d)$ $CH_{3}C \equiv N \rightarrow CH_{3}COCH_{3}$ | $(iv)$ $SnCl_{2}, HCl / H_{2}O$ |
Choose the most appropriate match :
Saponification (basic hydrolysis) of $C_6H_5-CO-^{18}OCH_3$ will yield. [$^{18}O$ = mass $-18$ isotope of oxygen]
Medium
View SolutionWhat are $A, B$ and $C$ in the following reactions?
Phthalic acid $+\, NH_3 \rightarrow A \xrightarrow{\Delta} B \xrightarrow{\text{High temperature}} C$
Phthalic acid $+\, NH_3 \rightarrow A \xrightarrow{\Delta} B \xrightarrow{\text{High temperature}} C$
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