In the following schematic diagram for the preparation of hydrogen gas as shown in the Figure,what would happen if the following changes are made?
$(a)$ In place of zinc granules,the same amount of zinc dust is taken in the test tube.
$(b)$ Instead of dilute sulphuric acid,dilute hydrochloric acid is taken.
$(c)$ In place of zinc,copper turnings are taken.
$(d)$ Sodium hydroxide is taken in place of dilute sulphuric acid and the tube is heated.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Hydrogen gas will evolve with greater speed because zinc dust has a larger surface area compared to zinc granules,which increases the rate of reaction.
$(b)$ Almost the same amount of hydrogen gas will be evolved as both are strong mineral acids.
$(c)$ Hydrogen gas will not be evolved because copper is less reactive than hydrogen and cannot displace it from the acid.
$(d)$ If sodium hydroxide is taken,hydrogen gas will be evolved upon heating:
$Zn + 2NaOH \to Na_2ZnO_2 + H_2$ (Sodium zincate is formed along with hydrogen gas).

Explore More

Similar Questions

Which of the following is a compound of hydrogen and oxygen?

What effect does dihydrogen gas $(H_2)$ have on litmus paper?

Which of the following is not a neutral oxide?

What is the percentage of $H_{2}SO_{4}$ in dilute sulfuric acid (in $\%$)?

$500 \ ml$ aqueous solution is prepared by dissolving $2$ moles of $HCl$ in water. What will be the molarity of this solution (in $M$)?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo