In the formula bar{x} = frac{Sigma f_{i} x_{i | vedclass

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(C) The formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$ is used to calculate the arithmetic mean of grouped data.In this formula,$f_{i}$ r

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sum of the frequencies of all the classes

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(C) The formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$ is used to calculate the arithmetic mean of grouped data.In this formula,$f_{i}$ represents the frequency of the $i$-th class interval,and $x_{i}$ represents the class mark (mid-value) of the $i$-th class interval.The symbol $\Sigma$ denotes the summation.Therefore,$\Sigma f_{i}$ represents the sum of the frequencies of all the classes,which is often denoted by $N$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$4$	$10$	$20$	$18$	$20$	$16$	$10$

Number of seats	$100-104$	$104-108$	$108-112$	$112-116$	$116-120$
Frequency	$15$	$20$	$32$	$18$	$15$

Class	$10-30$	$30-50$	$50-70$	$70-90$	$90-110$
Frequency	$17$	$f_{1}$	$32$	$f_{2}$	$19$

In the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$\Sigma f_{i}$ represents ........

Similar Questions

The formula to find the mean of an ungrouped data is ........

Find the mean of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $2$ $4$ $10$ $20$ $18$ $20$ $16$ $10$

An aircraft has $120$ passenger seats. The number of seats occupied during $100$ flights is given in the following table:

Number of seats $100-104$ $104-108$ $108-112$ $112-116$ $116-120$

Frequency $15$ $20$ $32$ $18$ $15$

Determine the mean number of seats occupied over the flights. (in $.92$)

For a given frequency distribution,the total frequency is $25$ and $\Sigma f_{i} x_{i} = 120$. Then,the mean is $\ldots$

The mean of the following frequency distribution is $60$ and the total frequency is $120$. Find the missing frequencies $f_{1}$ and $f_{2}$.

Class $10-30$ $30-50$ $50-70$ $70-90$ $90-110$

Frequency $17$ $f_{1}$ $32$ $f_{2}$ $19$

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