In the given $A.C.$ circuit,the instantaneous currents through the inductor and capacitor are $0.8 \,A$ and $0.4 \,A$ respectively. The instantaneous current through the resistor is:

$A$ capacitance of $\left(\frac{10^{-3}}{2 \pi}\right) F$,an inductance of $\left(\frac{100}{\pi}\right) mH$,and a resistance of $10 \Omega$ are connected in series with an $AC$ voltage source of $220 V, 50 Hz$. The phase angle of the circuit is (in $^{\circ}$)

In an $LCR$ series circuit, the potential difference across the terminals of the inductor, capacitor and resistor is $60 \text{ V}$, $30 \text{ V}$ and $40 \text{ V}$ respectively. Then the supply voltage will be equal to (in $\text{ V}$)

Write the differential equation of charge for $L-C-R$ series $AC$ circuit.

As shown in the figure,a series circuit connected across a $200\, V$,$60\, Hz$ line consists of a capacitor of capacitive reactance $30\,\Omega$,a non-inductive resistor of $44\,\Omega$,and a coil of inductive reactance $90\,\Omega$ and resistance $36\,\Omega$. The power dissipated in the coil is......$W$.

In a series resonant circuit,the $ac$ voltage across resistance $R$,inductance $L$,and capacitance $C$ are $5\, V$,$10\, V$,and $10\, V$ respectively. The $ac$ voltage applied to the circuit will be.....$V$.