In the given (V - T) diagram,what is the rela | vedclass

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(C) According to the ideal gas equation,$PV = nRT$Rearranging for $V$ in terms of $T$:$V = \left( \frac{nR}{P} \right) T$This represents a straight li

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$P_2 < P_1$

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(C) According to the ideal gas equation,$PV = nRT$Rearranging for $V$ in terms of $T$:$V = \left( \frac{nR}{P} ight) T$This represents a straight line passing through the origin,where the slope $m$ is given by:$m = \frac{V}{T} = \frac{nR}{P}$Since $n$ and $R$ are constants,the slope is inversely proportional to the pressure $P$ $(m \propto \frac{1}{P})$.From the given figure,the angle $	heta_2 > 	heta_1$,which implies that the slope of the line for $P_2$ is greater than the slope of the line for $P_1$:$(	ext{Slope})_2 > (	ext{Slope})_1$Since slope is inversely proportional to pressure,a higher slope corresponds to a lower pressure:$P_2 < P_1$

Column-$I$	Column-$II$
$(a)$ Boyle's law	$(i)$ Pressure
$(b)$ Charles's law	$(ii)$ Volume
	$(iii)$ Temperature

In the given $(V - T)$ diagram,what is the relation between pressures $P_1$ and $P_2 \,?$

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