In the given Cannizzaro reaction,the slowest step is:
$2PhCHO \xrightarrow{KOH} PhCH_2OH + PhCOO^-$

  • A
    The attack of $OH^-$ at the carbonyl group
  • B
    The transfer of hydride to the carbonyl group
  • C
    The abstraction of proton from the carboxylic acid
  • D
    The deprotonation of $PhCH_2OH$

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