In the given circuit diagram,when the current reaches a steady state,the charge on the capacitor of capacitance $C$ will be:

  • A
    $CE$
  • B
    $CE \frac{r_1}{r_1 + r_2}$
  • C
    $CE \frac{r_2}{r + r_2}$
  • D
    $CE \frac{r_1}{r_1 + r}$

Explore More

Similar Questions

Switch $S$ of the circuit shown in the figure is in position $1$ for a long time. At instant $t = 0$,it is thrown from position $1$ to $2$. Find the thermal power $P_1(t)$ generated in resistance $R_1$.

Difficult
View Solution

$A$ $4 \mu F$ capacitor and a resistance of $2.5 \, M\Omega$ are in series with a $12 \, V$ battery. Find the time after which the potential difference across the capacitor is $3$ times the potential difference across the resistor. (Given $\ln(2) = 0.693$)

When the switch $K$ is closed at $t = 0$,what can be said about the current passing through the resistor $AB$ in the given circuit?

Difficult
View Solution

In the circuit shown,when the key $K$ is pressed at time $t = 0$,which of the following statements about current $I$ in the resistor $AB$ is true?

Difficult
View Solution

In the given circuit,switch $S$ is closed at $t = 0$. The current $I$ in the figure at time $t$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo