In the hydrogen spectrum,if the shortest wavelength in the Balmer series is $\lambda$,then the shortest wavelength in the Brackett series is:

  • A
    $\lambda$
  • B
    $\lambda / 2$
  • C
    $4 \lambda$
  • D
    $9 \lambda$

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Similar Questions

The wavelength of the Lyman series is given by which of the following expressions?

Which of the following statement$(s)$ is(are) correct about the spectrum of hydrogen atom?
$(A)$ The ratio of the longest wavelength to the shortest wavelength in Balmer series is $9/5$.
$(B)$ There is an overlap between the wavelength ranges of Balmer and Paschen series.
$(C)$ The wavelengths of Lyman series are given by $\lambda = \frac{\lambda_0}{1 - 1/m^2}$,where $\lambda_0$ is the shortest wavelength of Lyman series and $m$ is an integer.
$(D)$ The wavelength ranges of Lyman and Balmer series do not overlap.

The second line of the Balmer series has a wavelength of $4861 Å$. The wavelength of the first line of the Balmer series is: (in $Å$)

If the electron in a hydrogen atom transits from the second orbit to the first orbit,in what region would the emitted radiation be?

Specify the quantum number for the limit wavelength of the spectral series of a hydrogen atom.

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