In the given reaction,the compound C is:C_6H_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction sequence is known as Kolbe's reaction.$1$. Phenol $(C_6H_5OH)$ reacts with $NaOH$ to form sodium phenoxide $(A)$: $C_6H_5OH + NaOH \r

Vedclass · Accepted Answer

Salicylic acid

Vedclass · Answer

(D) The reaction sequence is known as Kolbe's reaction.$1$. Phenol $(C_6H_5OH)$ reacts with $NaOH$ to form sodium phenoxide $(A)$: $C_6H_5OH + NaOH \rightarrow C_6H_5ONa + H_2O$.$2$. Sodium phenoxide reacts with $CO_2$ at $140 \ ^oC$ and $4-7 \ atm$ pressure to form sodium salicylate $(B)$: $C_6H_5ONa + CO_2 \rightarrow C_6H_4(OH)COONa$.$3$. Acidification of sodium salicylate with $HCl$ yields salicylic acid $(C)$: $C_6H_4(OH)COONa + HCl \rightarrow C_6H_4(OH)COOH + NaCl$.Thus,the final product $C$ is salicylic acid.

In the given reaction,the compound $C$ is:
$C_6H_5OH$ $\xrightarrow{NaOH} (A)$ $\xrightarrow{CO_2, 140 \ ^oC, (4-7 \ atm)} (B)$ $\xrightarrow{HCl} (C)$

Similar Questions

$C_6H_5OH \xrightarrow[Br_2]{OH^{\ominus}} ; $ Intermediate of the given reaction is/are

$4$-Hydroxybenzenesulphonic acid is treated with bromine water. The product formed is -

Phenol is

Write the chemical equations for the following reactions:
$(i)$ Reimer-Tiemann reaction
$(ii)$ Kolbe's reaction

Phenol can be distinguished from ethanol by the reagent

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the given reaction,the compound $C$ is:$C_6H_5OH$ $\xrightarrow{NaOH} (A)$ $\xrightarrow{CO_2, 140 \ ^oC, (4-7 \ atm)} (B)$ $\xrightarrow{HCl} (C)$