In the reaction:C_6H_5-H xrightarrow{[X] / Al | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given reaction is a Friedel-Crafts acylation reaction.In Friedel-Crafts acylation,benzene reacts with an acylating agent (such as an acid chlo

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(C) The given reaction is a Friedel-Crafts acylation reaction.In Friedel-Crafts acylation,benzene reacts with an acylating agent (such as an acid chloride or an acid anhydride) in the presence of a Lewis acid catalyst like $AlCl_3$ to form an aromatic ketone.For the product $C_6H_5-C(=O)-CH_2-C_6H_5$ (phenyl benzyl ketone),the acylating group is $C_6H_5-CH_2-CO-$.Option $(A)$ is $C_6H_5CH_2COCl$ (phenylacetyl chloride),which is an acid chloride.Option $(B)$ is $(C_6H_5-CH_2CO)_2O$ (phenylacetic anhydride),which is an acid anhydride.Both acid chlorides and acid anhydrides can act as acylating agents in the presence of $AlCl_3$ to produce the same ketone.Therefore,both $(A)$ and $(B)$ are correct.

In the reaction:
$C_6H_5-H \xrightarrow{[X] / AlCl_3} C_6H_5-C(=O)-CH_2-C_6H_5$
$[X]$ will be:

Similar Questions

Acetophenone can be obtained by the distillation of:

Which among the following compounds is treated with benzonitrile in dry ether followed by acid hydrolysis to obtain benzophenone?

What is obtained when calcium acetate is dry distilled?

Explain different methods of formation of benzaldehyde by chemical reactions.

For the reaction sequence: $P$ $\xrightarrow[2. H_3O^+]{1. CH_3MgBr} R$ $\xrightarrow[2. \Delta]{1. \text{dil. } NaOH} \text{4-methylpent-3-en-2-one}$,identify $P$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the reaction:$C_6H_5-H \xrightarrow{[X] / AlCl_3} C_6H_5-C(=O)-CH_2-C_6H_5$$[X]$ will be: